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CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi

CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi

Time allowed: 3 hours
Maximum Marks: 70

CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I

Question 1.
Define ‘order of a reaction’. [1]
Answer:
The sum of powers of the concentrations of the reactants in the rate law expression is called the order of a reaction.

Question 2.
What is meant by ‘shape-selective catalysis’? [1]
Answer:
Catalysis using selective absorbents like zeolites as a catalyst is called shape-selective catalysis. In this catalysis, small-sized molecules are absorbed in the pores and cavities of zeolites.

Question 3.
Differentiate between a mineral and an ore. [1]
Answer:

S.No.MineralOre
1.These are naturally occurring chemical substances obtained from earth crust by mining.Ores are those mine­rals from which me­tals can be extracted profitably and conve­niently.
2.All minerals are not ores.All ores are minerals.

Question 4.
What is meant by ‘lanthanoid contraction’? [1]
Answer:
The lanthanoid contraction refers to the steady and regular decrease in atomic radii along the period from La+3 to Lu+3.

Question 5.
Write the IUPAC name of the following compound:
CH2=CHCH2Br [1]
Answer:
3-Bromo-1-propene

Question 6.
Draw the structure of 4-chloropentan-2-one. [1]
Answer:
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q6

Question 7.
How would you convert ethanol to ethene? [1]
Answer:
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q7

Question 8.
Rearrange the following in increasing order of their basic strengths: [1]
C6H5NH2, C6H5N(CH3)2, (C2H5)2NH and CH3NH2.
Answer:
C6H5NH2 < C6H5N(CH3)2 < CH3NH2 < (C2H5)2NH

Question 9.
Explain how you can determine the atomic mass of an unknown metal if you know its mass density and the dimensions of the unit cell of its crystal. [2]

Question 10.
Calculate the packing efficiency of a metal crystal for a simple cubic lattice. [2]
Answer:
Edge length = a

Question 11.
State the following: [2]
(i) Raoult’s law in its general form in reference to solutions.
(ii) Henry’s law about partial pressure of a gas in a mixture.
Answer:
(i) Raoult’s Law: The partial vapour pressure of each component of a solution is equal to the vapour pressure of pure component multiplied by its mole fraction in the solution.
P = PAxA+PBxB
Where
P = Total vapour pressure of a solution.
PA and PB = vapour pressure of components A and B.
xA and xB = mole fractions of components A and B.

(ii) Henry’s Law: It states that the partial pressure of a gas in the vapour phase (P) is directly proportional to the mole fraction of gas (x) in the solution and is expressed as
P = KHx
where KH is Henry constant.

Question 12.
What do you understand by the rate law and rate constant of a reaction? Identify the order of a reaction if the units of its rate constant are: [2]
(i) L-1 mol s-1
(ii) L mol-1 s-1
Answer:
Rate law of a chemical reaction is the expression relating the rate of reaction to the concentrations or pressures of various reactants taking part in the reaction.
The rate of reaction at a unit concentration of all reactants is known as the rate constant (K)

  • Zero-order
  • Second-order

Question 13.
The thermal decomposition of HCO2H is a first-order reaction with a rate constant of 2.4 × 10-3 s-1 at a certain temperature. Calculate how long will it take for three-fourths of the initial quantity of HCO2H to decompose, (log 0.25 = -0.6021) [2]
Answer:
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q13
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q13.1

Question 14.
Describe the principle controlling each of the following processes: [2]

  1. Vapour phase refining of titanium metal
  2. Froth floatation method of concentration of a sulphide ore

Answer:

  1. Titanium is converted to its volatile form which is evaporated and then decomposed to give pure titanium.
  2. The ore particles get adsorbed on oil droplets and come to the surface where they can be collected as froth gangue is wetted by water and gets settle down.

Question 15.
How would you account for the following: [2]

  1. Cr2+ is reducing in nature while with the same d-orbital configuration (d4) Mn3+ is an oxidizing agent.
  2. In a transition series of metals, the metal which exhibits the greatest number of oxidation states occurs in the middle of the series.

Answer:

  1. Cr2+ has configuration d4 which easily changes to d3 due to stable half-filled 12g orbitals. Therefore, Cr2+ is reducing agent and Mn3+ easily changes to Mn2+ and acts as an oxidizing agent.
  2. Due to the presence of more unpaired electrons and more number of partially filled orbitals in the middle of a transition series, these metals exhibit the greatest number of oxidation states.

Question 16.
Complete the following chemical equations: [2]
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q16
OR
State reasons for the following:
(i) Cu (i) ion is not stable in an aqueous solution.
(ii) Unlike Cr3+, Mn2+, Fe3+ and the subsequent other M2+ ions of the 3d series of elements, the 4d and the 5d series metals generally do not form stable cationic species.
Answer:
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q16.1
OR
(i) Cu2+ is more stable than Cu+ because hydration energy of Cu2+ is high and it is, therefore, stable in aqueous solution. Therefore, Cu+ disproportionates to Cu2+ and Cu.
2Cu+ → Cu2+ + Cu
(ii) Because of Lanthanoid contraction, an expected increase in size does not occur. That is why they do not form stable cations.

Question 17.
Explain what is meant by the following: [2]
(i) Peptide linkage
(ii) Pyranose structure of glucose
Answer:
(i) Peptide linkage is the peptide bond formed between amino acids. It is a covalent bond formed between an amino group of one molecule and a carboxylic acid group of another molecule, causing the release of one molecule of water.
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q17
(ii) The cyclic structure of glucose is called pyranose because it resembles the pyran ring. Its structure includes a six-membered ring with 5-carbon atoms and one oxygen atom having no double bonds.
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q17.1

Question 18.
Write the main structural difference between DNA and RNA. Of the four bases, name those which are common to both DNA and RNA. [2]
Answer:

S.No.DNARNA
1.Sugar present in DNA, is 2-deoxy D-riboseIn RNA, sugar is D-ribose
2.DNA is a double stranded moleculeRNA is a single-stranded molecule
3.DNA can replicateRNA can not replicate

Adenine, cytokine and guanine are bases present in both DNA and RNA

Question 19.
A solution prepared by dissolving 8.95 mg of a gene fragment in 35.0 mL of water has an osmotic pressure of 0.335 torrs at 25°C. Assuming that the gene fragment is a non-electrolyte, calculate its molar mass. [3]
Answer:
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q19

Question 20.
Classify colloids where the dispersion medium is water. State their characteristics and write an example of each of these classes. [3]
OR
Explain what is observed when
(i) an electric current is passed through a Solution
(ii) a beam of light is passed through a Solution
(iii) an electrolyte (say NaCl) is added to ferric hydroxide sol
Answer:
Colloids can be classified into two types where the dispersion medium is water. They are as follows:
1. Hydrophilic Colloids or Lyophilic: The substances when mixed with dispersion medium form colloidal solution directly are called hydrophilic colloids. They are quite stable, reversible solutions and can’t get precipitated easily, e.g., Gum starch, etc.
2. Hydrophobic Colloids or Lyophobic: The substances which do not form a colloidal solution with dispersion medium are called hydrophobic colloids. They are unstable, irreversible solutions and can be easily precipitated, e.g., Metals and their sulphides.
OR
(i) When an electric current is passed through a solution, then positively charged ions move towards the cathode and negatively charged ions move towards the anode. Then they get coagulate.
This is known as Electrophoresis.

(ii) When a beam of strong light is passed through the solution, the light gets scattered by the colloidal particles and the path of light becomes visible. This is known as the Tyndall effect.

(iii) When NaCl is added to ferric hydroxide sol then a negatively charged solution is obtained with the absorption of OH ion.

Question 21.
How would you account for the following: [3]

  1. H2S is more acidic than H2O.
  2. The N-O bond in NO2 is shorter than the N-O bond in NO3
  3. Both O2 and F2 stabilize high oxidation states but the ability of oxygen to stabilize the higher oxidation state exceeds that of fluorine.

Answer:

  1. Size of sulphur is larger than oxygen due to which S-H bond length increases and hence the bond dissociation energy of S-H is less than O-H. Therefore S-H easily loses H+ and is more acidic than H2O.
  2. Due to the tendency of nitrogen to form pπ-pπ multiple bonds, there is a difference in N-O bond lengths of NO2 and NO3.
  3. Due to the property of oxygen to form double bonds with the metal atoms, oxygen stabilizes the higher oxidation state even more than fluorine.

Question 22.
Explain the following terms giving a suitable example in each case: [3]

  1. Ambident ligand
  2. Denticity of a ligand
  3. Crystal field splitting in an octahedral field

Answer:

  1. Ligands which can ligate to the central atom in two places ligands such as SCN which can attach at either S atom or N atom are called ambidentate ligand.
  2. The number of donor atoms of a ligand, when bound with the central atom in a coordination complex, is called its denticity.
  3. The splitting of five degenerated d-orbitals in two sets, one with three orbitals and another with two orbitals is known as crystal field splitting.

Question 23.
Rearrange the compounds of each of the following sets in order of reactivity towards SN2 displacement: [3]

  1. 2-Bromo-2-methyl butane, 1-Bromopentane, 2-Bro-neopentane
  2. 1-Bromo-3-methyl butane, 2-Bromo-2- methyl-butane, 2-Bromo-3-methyl butane
  3. 1-Bromobutane, 1-Bromo-2, 2-dimethylpropane, 1- Bromo-2- methyl butane.

Answer:

  1. 1-bromopentane > 2-bromopentane > 2-bromo-2-methylbutane.
  2. 1-bromo-3 methylbutane > 2-bromo-3- methylbutane > 2-bromo-2-methyl butane.
  3. 1-bromobutane > 1-bromo-3-methylbutane > 1-bromo-2, 2-dimethylpropane.

Question 24.
How would you obtain the following: [3]
(i) Benzoquinone from phenol
(ii) 2-Methylpropan-2-ol from methyl magnesium bromide
(iii) Propan-2-ol from propene
Answer:
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q24
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q24.1
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q24.2

Question 25.
State reasons for the following: [3]
(i) pKb value for aniline is more than that for methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not soluble in water.
(iii) Primary amines have higher boiling points than tertiary amines.
Answer:
(i) A higher value of pKb means lower basicity, therefore, aniline is less basic than methylamine because in aniline the lone pair of electrons on N atom gets delocalized over the benzene ring and remains unavailable for protonation due to resonance but this is absent in methylamine.

(ii) Ethylamine forms H-bonds with water therefore, it is soluble in water but aniline does not form H-bonds with water due to its larger hydrocarbon part and is insoluble in water.

(iii) In primary amines, two H-atoms are attached to N-atom and they undergo intermolecular H-bonding, but tertiary amines due to the absence of H-atom on N-atom do not undergo H-bonding. Therefore, primary amines have a higher boiling point than tertiary amines.

Question 26.
Draw the structures of the monomers of the following polymers: [3]
(i) Polythene
(ii) PVC
(iii) Teflon
Answer:
(i) Ethene —CH2=CH2
(ii) Vinyl chloride —HCH2=CHCl—
(iii) Tetrafluoroethylene —CF2=CF2

Question 27.
What are the following substances? Give one example of each. [3]

  1. Food preservatives
  2. Synthetic detergents
  3. Antacids

Answer:

  1. Chemicals added to food to prevent its spoilage by killing or preventing the growth of microorganisms like bacteria, yeasts and moulds, e.g., sodium benzoate.
  2. Synthetic detergents are sodium or potassium salts of long-chain sulphonic acids. They don’t precipitate in hard water, e.g., Sodium lauryl sulphate.
  3. Antacids are chemicals consumed to get relief from acidity in the stomach by neutralizing excess acid, e.g., milk of magnesia.

Question 28.
(a) What type of battery is lead storage battery? Write the anode and cathode reactions and the overall cell reaction occurring in the operation of a lead storage battery. [5]
(b) Calculate the potential for half-cell containing 0.10 M K2Cr2O7 (aq), 0.20 M Cr3+ (aq) and 1.0 × 10-4 M H+ (aq). The half-cell reaction is and the standard electrode potential is given as E0 = 1.33 V.
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q28
OR
(a) How many moles of mercury will be produced by electrolyzing 1.0 M Hg(NO3)2 solution with a current of 2.00 A for 3 hours? [Hg(NO3)2 = 200.6 g mol-1]
(b) A voltaic cell is set up at 25°C with the following half-cells Al3+ (0.001 M) and Ni2+ (0.50 M). Write an equation for the reaction that occurs when the cell generates an electric current and determine the cell potential.
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q28.1
Answer:
(a) The lead storage battery is a secondary cell (rechargeable). The electrode reaction is as follows:
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q28.2
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q28.3
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q28.4

Question 29.
(a) Draw the structures of the following molecules: [5]
(i) (HPO3)3
(ii) BrF3
(b) Complete the following chemical equations:
(i) HgCl2 + PH3
(ii) SO3 + H2SO4
(iii) XeF4 + H2O →
OR
(a) What happens when
(i) Chlorine gas is passed through a hot concentrated solution of NaOH?
(ii) Sulphur dioxide gas is passed through an aqueous solution of a Fe(III) salt?
(b) Answer the following:
(i) What is the basicity of H3PO3 and why?
(ii) Why does fluorine not play the role of a central atom in interhalogen compounds?
(iii) Why do noble gases have very low boiling points?
Answer:
(a) (ii) BrF3
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q29
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q29.1

(b) (ii) Since fluorine is the most electro-negative halogen, it does not acts as a central atom in interhalogen compounds due to the absence of d-orbital.
(iii) Noble gases are monoatomic with weak Vander Waals forces of attraction and hence have low boiling points.

Question 30.
(a) Illustrate the following name reactions: [5]
(i) Cannizzaro’s reaction
(ii) Clemmensen reduction
(b) How would you obtain the following:
(i) But-2-enal from ethanal
(ii) Butanoic acid from butanol
(iii) Benzoic acid from ethylbenzene
OR
(a) Give chemical tests to distinguish between the following:
(i) Benzoic acid and ethyl benzoate
(ii) Benzaldehyde and acetophenone
(b) Complete each synthesis by giving missing reagents or products in the following:
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q30
Answer:
(a) (i) Aldehydes having no a -hydrogen atom undergoes self oxidation and reduction on treatment with concentrated alkali and produces alcohol and carboxylic acid salt.
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q30.1

(iii) Reduction of aldehydes and ketones to their respective hydrocarbons. On treating with zinc amalgam and concentrated hydrochloric acid
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q30.2
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q30.3
OR
(a) (i) Benzoic acid gives CO2 gas on reacting with NaHCO3 but ethyl benzoate does not
(ii) Acetophenone gives iodoform test but
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set I Q30.4

CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set II

Note: Except for the following questions, all the remaining questions have been asked in the previous set.

Question 2.
What are lyophobic colloids? Given one example for them. [1]
Answer:
Colloids in which the colloidal particles have no affinity for the dispersion medium and they do not form a colloidal solution are lyophobic colloids, like, Al(OH)3 and AS2S3 sols.

Question 3.
Why is it that only sulphide ores are concentrated by ‘froth floatation process’? [1]
Answer:
Due to the affinity of heavy oil droplets to adsorb sulphide particles. The ore particles come on the surface as froth, gangue particles are wetted by water and get settle down.

Question 5.
Write the IUPAC name of the following compound: [1]
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set II Q5
Answer:
3-Bromo-2-methyl prop-1-ene

Question 6.
Draw the structure of 2, 6-Dimethylphenol. [1]
Answer:
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set II Q6

Question 9.
Define the following terms in relation to crystalline solids: [2]
(i) Unit Cell
(ii) Coordination number

Question 12.
A reaction is of second order with respect to a reactant How is the rate of reaction affected if the concentration of the reactant is reduced to half? What is the unit of the rate constant for such a reaction? [2]
Answer:
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set II Q12

Question 14.
Describe the principle controlling each of the following processes: [2]
(i) Zone refining of metals
(ii) Electrolytic refining of metals
Answer:
(i) Zone refining of Metals: It is based on the principle that impurities are more soluble in the molten state of metal than in the solid-state

(ii) Electrolytic refining: Impure metal is made of an anode, a thin sheet of pure metal is made of a cathode and a salt of the metal is used as an electrolyte. On passing current, metal from anode goes into the solution and ions in the solution reduce on cathode leading to deposition of pure metal.

Question 15.
Explain giving a suitable reason for each of the following: [2]
(i) Transition metals and their compounds are generally found to be good catalysts.
(ii) Metal-metal bonding is more frequent for the 4d and the 5d series of transition metals than that for the 3d series.
Answer:
(i) Due to the presence of vacant orbitals and tendency to form a large number of oxidation states, transition metals have a high tendency to form complexes and hence acts as catalysts.

(ii) In transition metals of 4d and 5d series, the 4d and 5d electrons are at a greater distance from the nucleus, therefore, they are less tightly held to the atom by the nucleus and hence contribute more to metallic bonding as compared to transition metals of 3d series.

Question 19.
What mass of NaCl must be dissolved in 65.0 g of water to lower the freezing point of water by 7.50°C? The freezing point depression constant (Kf) for water is 1.86°C/m. Assume Van’t Hoff factor for NaCl is 1.87. (Molar mass of NaCl = 58.5 g) [3]
Answer:
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set II Q19

Question 22.
Write the structures and names of all the stereoisomers of the following compounds: [3]
(i) [Co(en3)]Cl3
(ii) [Pt(NH3)2Cl2]
(iii) [Fe(NH3)4Cl2]Cl
Answer:
(i) Stereoisomerism is of two types:
(1) Geometrical isomerism
(2) Optical isomerism
[Co(en)3]Cl3: Tris (ethylenediamine) cobalt (III) chloride
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set II Q22
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set II Q22.1
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set II Q22.2

Question 27.
(a) Differentiate between a disinfectant and an antiseptic. Give one example of each.
(b) What is a tincture of iodine and what is it used for? [3]
Answer:

S.No.DisinfectantAntiseptic
1.Chemical substances used to kill microor­ganismsChemical substances which prevent the growth of microorganisms and may even loll them.
2.They are applied on non-living objectsThey are safe to apply to live tissues.
3.They are used in drains, toilets, floors etc.They are used on wounds, cut, ulcers etc.
4.Example: Phenol (1%)Example: Soframycin

(b) 2-3% solution of iodine in alcohol and water is called tincture iodine and is widely used as an antiseptic.

CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set III

Note: Except for the following questions, all the remaining questions have been asked in previous sets.

Question 1.
Define ‘activation energy’ of a reaction. [1]
Answer:
Activation energy is the minimum energy that is to be provided to the reactants for the reaction to take place.

Question 2.
What is meant by ‘reverse osmosis’? [1]
Answer:
When a pressure higher than the osmotic pressure is applied the solvent will flow from the solution into the pure solvent through the semipermeable membrane, called reverse osmosis.

Question 3.
What type of ores can be concentrated by magnetic separation method? [1]
Answer:
Ores with different magnetic properties and impurities which are magnetic in nature can be concentrated by magnetic separation method. e.g. Chromite (FeO.Cr2O3), Magnetite (Fe3O4)

Question 14.
Describe the principle controlling each of the following processes: [2]
(i) Preparation of cast iron from pig iron.
(ii) Preparation of pure alumina (Al2O3) from bauxite ore.
Answer:
(i) Preparation of cast iron from pig iron: The iron obtained from a blast furnace is called pig iron. Cast iron is prepared by melting pig iron with scrap iron and coke using hot air blast. It has slightly lower carbon content (about 3%). It is extremely hard and brittle.

(ii) Preparation of pure alumina from bauxite ore: The principal ore of aluminium is bauxite Al2O3xH2O. Bauxite is concentrated by digesting the powdered ore with a concentrated solution of NaOH at 473-523K. The Al2O3 is leached out as sodium aluminate. The sodium aluminate is neutralized by passing CO2 gas and hydrated Al2O3 is precipitated which is filtered, dried and heated to give pure Al2O3.
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set III Q14

Question 15.
Explain giving reasons: [2]
(i) Transition metals and their compounds generally exhibit paramagnetic behaviour.
(ii) The chemistry of actinoids is not so smooth as that of lanthanoids.
Answer:
(i) Transition metals and their compounds exhibit a paramagnetic behaviour due to the presence of unpaired electrons in the Penultimate shell of d-orbital.

(ii) Lanthanoids show a limited number of oxidation states, +2, +3, +4 because of the large energy gap between 4f and 5d subshells. Actinoids show a number of oxidation states +4, +5, +6, +7 due to the small energy difference between 5f, 6d and 7s subshells.

Question 18.
Write such reactions and facts about glucose which cannot be explained by its open-chain structure. [2]
Answer:
Limitations of open chain structure of glucose:

  • Glucose does not form NaHSO3 as an additional product.
  • Glucose penta-acetate does not react with NH2OH due to the absence of the aldehyde group.

Question 21.
How would you account for the following: [3]
(i) NF3 is an exothermic compound but NCl3 is not.
(ii) The acidic strength of compounds increases in the order PH3 < H2S < HCl
(ii) As electronegativity increases in the same period from left to right so their electronegativity is in the increasing order P < S < Cl. Therefore, acidic strength increases in the order PH3 < H2S < HCl
(iii) SF6 is protected by six F atoms and hence does not allow to attack sulphur atom.

Question 22.
Write the state of hybridization, the shape and the magnetic behaviour of the following complex entitles: [3]

  1. [Cr(NH3)4Cl2]Cl
  2. [Co(en)3]Cl3
  3. K2[Ni(CN)4]

Answer:

  1. d2sp3, octahedral, diamagnetic
  2. d2sp3, octahedral, diamagnetic
  3. dsp2, square planar, diamagnetic

Question 26.
Write the names and structures of the monomers of the following polymers: [3]
(i) Buna-S
(ii) Dacron
(iii) Neoprene
Answer:
(i) Buna-S: 1, 3-Butadiene
CH2=CH-CH-CH2 and styrene C6H5CH=CH2
(ii) Dacron: Ethylene glycol HOCH2CH2OH, Terephthalic acid
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set III Q26
(iii) Neoprene: Chloroprene
CBSE Previous Year Question Papers Class 12 Chemistry 2011 Outside Delhi Set III Q26.1

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