# NCERT solution class 11 chapter 8 Binomial Theorem exercise 8.3 mathematics

## EXERCISE 8.3

#### Question 1:

Find ab and n in the expansion of (a + b)n if the first three terms of the expansion are 729, 7290 and 30375, respectively.

It is known that (+ 1)th term, (Tr+1), in the binomial expansion of (b)n is given by .

The first three terms of the expansion are given as 729, 7290, and 30375 respectively.

Therefore, we obtain Dividing (2) by (1), we obtain Dividing (3) by (2), we obtain From (4) and (5), we obtain Substituting n = 6 in equation (1), we obtain

a6 = 729 From (5), we obtain Thus, a = 3, b = 5, and n = 6.

#### Question 2:

Find a if the coefficients of x2 and x3 in the expansion of (3 + ax)9 are equal.

It is known that (+ 1)th term, (Tr+1), in the binomial expansion of (b)n is given by .

Assuming that x2 occurs in the (r + 1)th term in the expansion of (3 + ax)9, we obtain Comparing the indices of x in x2 and in Tr + 1, we obtain

r = 2

Thus, the coefficient of x2 is Assuming that x3 occurs in the (k + 1)th term in the expansion of (3 + ax)9, we obtain Comparing the indices of x in x3 and in Tk+ 1, we obtain

= 3

Thus, the coefficient of x3 is It is given that the coefficients of x2 and x3 are the same. Thus, the required value of a is .

#### Question 3:

Find the coefficient of x5 in the product (1 + 2x)6 (1 – x)7 using binomial theorem.

Using Binomial Theorem, the expressions, (1 + 2x)6 and (1 – x)7, can be expanded as  The complete multiplication of the two brackets is not required to be carried out. Only those terms, which involve x5, are required.

The terms containing x5 are Thus, the coefficient of x5 in the given product is 171.

#### Question 4:

If a and b are distinct integers, prove that a – b is a factor of an – bn, whenever n is a positive integer.

[Hint: write an = (a – b b)n and expand]

In order to prove that (a – b) is a factor of (an – bn), it has to be proved that

an – bn = k (a – b), where k is some natural number

It can be written that, a = a – b + b This shows that (a – b) is a factor of (an – bn), where n is a positive integer.

#### Question 5:

Evaluate .

Firstly, the expression (a + b)6 – (a – b)6 is simplified by using Binomial Theorem.

This can be done as #### Question 6:

Find the value of .

Firstly, the expression (x + y)4 + (x – y)4 is simplified by using Binomial Theorem.

This can be done as #### Question 7:

Find an approximation of (0.99)5 using the first three terms of its expansion.

0.99 = 1 – 0.01 Thus, the value of (0.99)5 is approximately 0.951.

#### Question 8:

Find n, if the ratio of the fifth term from the beginning to the fifth term from the end in the expansion of In the expansion, ,

Fifth term from the beginning Fifth term from the end Therefore, it is evident that in the expansion of , the fifth term from the beginning is and the fifth term from the end is . It is given that the ratio of the fifth term from the beginning to the fifth term from the end is . Therefore, from (1) and (2), we obtain Thus, the value of n is 10.

#### Question 9:

Expand using Binomial Theorem .

Using Binomial Theorem, the given expression can be expanded as Again by using Binomial Theorem, we obtain From (1), (2), and (3), we obtain #### Question 10:

Find the expansion of using binomial theorem.

Using Binomial Theorem, the given expression can be expanded as Again by using Binomial Theorem, we obtain From (1) and (2), we obtain error: Content is protected !! 