NCERT Solution class 7 chapter 2 exercise 2.1

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Exercise 2.1

Question 1

Solve :

(i) $2-\dfrac{3}{5}$

Sol :

$\dfrac{2}{1}-\dfrac{3}{5}$ $=\dfrac{2\times 5}{1\times 5}-\dfrac{3}{5}$ $=\dfrac{10-3}{5}$ $=\dfrac{7}{5}$

(ii) $4+\dfrac{7}{8}$

Sol :

$\dfrac{4}{1}+\dfrac{7}{8}$ $=\dfrac{4\times 8}{8}+\dfrac{7}{8}$ $=\dfrac{(4\times 8)+7}{8}$ $=\dfrac{39}{8}$ $=4\dfrac{7}{8}$

(iii) $\dfrac{3}{5}+\dfrac{2}{7}$

Sol :

$\dfrac{3}{5}+\dfrac{2}{7}$ $= \dfrac{3\times 7}{5\times 7}+\dfrac{2\times 5}{7\times 5}$ $=\dfrac{21+10}{35}$ $=\dfrac{31}{35}$

(iv) $\dfrac{9}{11}-\dfrac{4}{15}$

Sol :

$\dfrac{9}{11}-\dfrac{4}{15}$ $\dfrac{}{}-\dfrac{}{}$

(v) $\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}$

Sol :

$\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}$ $\dfrac{}{}+\dfrac{}{}+\dfrac{}{}$ $=\dfrac{}{}$ $=\dfrac{26}{10}$ $=\dfrac{13}{5}$ $=2\dfrac{3}{5}$

(vi) $2\dfrac{2}{3} + 3 \dfrac{1}{2}$

Sol :

$2\dfrac{2}{3} + 3 \dfrac{1}{2}$

(vii) $8\dfrac{}{2}-3\dfrac{5}{8}$

Sol :

$8\dfrac{}{2}-3\dfrac{5}{8}$

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