# Exercise 2.6

Question 1

Find:

(i)

Sol :

= 1.2

(ii)

Sol :

= 36.8

(iii)

Sol :

= 13.55

(iv)

Sol :

= 80.4

(v)

Sol :

= 0.35

(vi)

Sol :

= 844.08

(vii)

Sol :

= 1.72

Question 2

Find the area of rectangle whose length is 5.7 cm and breadth is 3 cm.

Sol :

Length = 5.7 cm

Breadth = 3 cm

Area = Length x Breadth

Area

Question 3

Find:

(i)

Sol :

= 13

(ii)

Sol :

= 368

(iii)

Sol :

= 1537

(iv)

Sol :

= 1680.7

(v)

Sol :

= 3110

(vi)

Sol :

= 15610

(vii)

Sol :

= 362

(viii)

Sol :

= 4307

(ix)

Sol :

= 5

(x)

Sol :

= 0.8

(xi)

Sol :

= 90

(xii)

Sol :

= 30

Notes : We know that when a decimal number is multiplied by 10, 100, 1000, the decimal point in the product is shifted to the right by as many places as there are zeroes.

Question 4

A two-wheeler covers a distance of 55.3 km in one litre of petrol. How much distance will it cover in 10 litres of petrol?

Sol :

Distance covered in 1 litre of petrol = 55.3 km

Distance covered in 10 litre of petrol = 553 km

Therefore, it will cover 553 km distance in 10 litre petrol.

Question 5

Find:

(i)

Sol :

= 0.75

(ii)

Sol :

= 5.17

(iii)

Sol :

= 63.36

(iv)

Sol :

= 4.03

(v)

Sol :

= 0.025

(vi)

Sol :

= 1.680 or 1.68

(vii)

Sol :

= 0.0214

(viii)

Sol :

= 10.5525

(ix)

Sol :

= 1.0101

(x)

Sol :

= 110.011