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S.chand publication solution of class 6 chapter 3 exercise 3 C

EXERCISE 3 C


1. Fill in the blanks.
(i) (+8) – (-3) = (+8) + ___ = ___
(ii) (-9) – (-4) = (-9) + ___ = ___
(iii) (-6) – (+2) = (-6) + ___ = ___
(iv) (+13) – (+15) = (+13) + ___ = ___

2. Rewrite each sentence as an addition sentence and find the answer
(i) (-12) – (-14) = ___ + ___ = ___
(ii) (+15) – (-17) = ___ + ___ = ___
(iii) (+10) – (+16) = ___ + ___ = ___
(iv) (-48) – (+13) = ___ + ___ = ___

3.Subtract each of the following using the number line.
(i) (-7) – (-2)
(ii) (+5) – (-3)
(iii) (+9) – (+6)
(iv) (-8) – (+2)

4.Subtract :
(i) (-20) from 7
(ii) (-16) from (-14)
(iii) (+9) – (+6)
(iv) (-8) – (+2)

5.Evaluate :
(i) (-3)-(-7)+11
(ii) 27-(-19)+(-40)
(iii) 15+(-19)-13-(-10)
(iv) 25-[(-8) + (-2)]

6.Fill in the blanks using < , > or = to make each sentence true.
(i) (-6) – (-3) ___ (+7) – (+10)
(ii) (+5) + (-6) ___ -2 – (+3)
(iii) -11 – (+14) ___ (+11) + (-14)
(iv) (+8) – (-5) ___ (-1) – (+2)

7.Subtract:
(i) The sum of (-262) and 132 from 100.
(ii) The sum of (-434) and (-166) from the sum of 389 and (-532)

8.Mercury at room temperature is a liquid. Its melting point is -39°C. The freezing point of alcohol is —114°C. How much warmer is the melting point of mercury than the freezing point of alcohol?

9.In a card game, it is possible to have negative score. If Ayesha‘s score is 25, what will be her score, if she loses 28 points?

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